THE HOLY MOLY CONVERSIONS~

HOLY MOLY! now, we are talking about Harder Mole Conversions...

Well, they aren't necessarily much harder. If you master the basic stuff, this should be easy!

One thing you HAVE to keep in memory is THIS: MOLE MAP!-> you will never get lost with it!

Now, recall that MOLE is defined as the amount of substance that contains 6.022 X 10^23 atoms or molecules or subatomic particles. This numeric value 6.022 X 10^23 is also called as Avogadro's number.

So, a mole of any substance (atom or molecule) would be equal to the atomic mass/ molecular mass of that substance in gram.

Calculation1: for Element: Grams to Moles to Atoms

Lets calculate the number of atoms in 80g of calcium.
Steps to be followed:
1)  Find the molar mass of element
2) Conversion of mass ( 80g ) into moles.
3) Getting the multiplication of obtained moles by avogadro's number to get the number of atoms.
Since we Know that
Atomic mass of Ca= 40 g/mole
so, the number of moles in 80g of Ca = given mass / atomic mass
                                                                   = 80g / 40 g/mol = 2 moles
Here we got the 2 moles of Ca from 80g of Ca.
Now, 1 mole of Ca = 6.022 x 10^23 atoms of Ca            ( By definition )
 Therefore, 2 moles of Ca = 2 X 6.022 X 10^23 atoms
                                               = 1.204 X 10^24 atoms of Ca
Thus, we got that
80g of calcium contains 1.204 X 10^24 atoms of the substance Ca.

Calculation 2: for Compound: Grams to Moles to Atoms

Lets calculate the no. of atoms in a compound, say 80g NaOH
Steps to be followed:
1) Find the molecular mass of substance ( here, 40g / mole)
2) Find the moles of this mass
3) convert this moles into number of molecules of substance
4) get the individual number of  constituent elementary atoms
Here we know the molar mass of NaOH= 40 g/mole
So, the no. of moles in 80g  of NaOH = 80g/ 40 g/mole
                                                                      = 2 moles
Now, since 1 mole of NaOH = 6.022 X 10^23 molecules of NaOH
 So,  2 moles of NaOH = 2* 6.022 x 10^23 molecules of NaOH = 1.204 X 10^24 molecules of NaOH
Now, calculating the individual constituents elementary atoms
Constituents                         1 molecule of NaOH                                          1.204 X 10^24 molecules of NaOH


Na                                                        1                                                                  1* 1.204 x 10^24 = 1.204 X 10^24 atoms of Na

O                                                           1                                                                 1* 1.204 x 10^24 = 1.204 X 10^24 atoms of O

H                                                           1                                                                 1* 1.204 x 10^24 = 1.204 X 10^24 atoms of H


THe MOLE mAP!~
               x 1mol/MMg                x Avagadro's# p./1mole        x # atoms/1 molecules  
Grams ------------> Moles -------------------> Ptcl-------># of atoms 

   x 1molecules/# of atoms          x 1mol/Avagadro's#        x 1 mol/MMG
  # of atoms -----> Ptcl-------> Moles ------> Grams        
Basically follow the map step by step, never try to be smart and skip one step!!